Answer
Choice E.
Work Step by Step
Equation 11–11a tells us that the period of a pendulum is proportional to the square root of its length and inversely proportional to the square root of g, $T=2 \pi \sqrt{\frac{L}{g}}$.
The starting angle (i.e., amplitude of oscillation) does not affect the period of the pendulum. Both oscillations have the same period.
