Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Search and Learn - Page 291: 5

Answer

$121.7N$

Work Step by Step

$F_G$ of water, tank, and brick is equal to $100N+F_B$ 100 Newtons, mass of water and tank plus the buoyancy force on the brick. $F_B=\rho_FVg$ $m=\frac{50N}{9.81m/s^2}=5.10kg$ $V=\frac{\rho_B}{m_B}=\frac{5.10kg}{2.3\times10^3kg/m^3}=2.22\times10^{-3}m^3$ $F_B=(1.00\times10^3kg/m^3)(2.22\times10^{-3}m^3)(9.81m/s^2)$$=21.7N$ $F_G=121.7N$
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