Answer
0.8547.
Work Step by Step
The specific gravity of the other fluid is the ratio of its density to that of water.
$$SG=\frac{\rho_{fluid}}{\rho_{water}}=\frac{(m_f/V_f)}{(m_w/V_w)}$$
The same volume of each fluid is used.
$$=\frac{m_f}{m_w}=\frac{89.22g-35.00g}{98.44g-35.00g}=0.8547$$
