Answer
$P_g=1.118\times10^4\frac{N}{m^2}$
Work Step by Step
$E_P=E_K$
$gh_n=\frac{v_n^2}{2}$
$v_n=1.53\frac{m}{s}$
$A_nv_n=A_pv_p$
$v_p=0.383\frac{m}{s}$
$P_g=\frac{1}{2}\rho(v_n^2-v_p^2)+\rho g(y_n-y_p)=1.118\times10^4\frac{N}{m^2}$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 10 - Fluids - General Problems - Page 290: 93
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