Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - General Problems - Page 290: 88

Answer

1 watt.

Work Step by Step

The work done during 1 heartbeat is the force on the fluid, multiplied by the distance that the fluid moves. This is also equal to pressure times volume. $$Power=\frac{PV}{t}$$ $$=\frac{(105mm-Hg)(\frac{133\;N/m^2}{1\;mm-Hg})(70\times10^{-6}m^3)}{(\frac{1}{70}min)(\frac{60\;s}{min})}\approx\;1W$$
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