Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 1 - Introduction, Measurement, Estimating - General Problems - Page 20: 46

Answer

About 3 feet across.

Work Step by Step

The volume of a sphere is $V=\frac{4 \pi R^3}{3}$. Solve for the radius $R=(\frac{3V}{4 \pi})^{1/3}$. For a 1-ton rock, first find the volume. $$V=(1T)(\frac{2000lb}{1T}\frac{1ft^3}{186lb})=10.8ft^3$$ $$d=2R=2(\frac{3V}{4 \pi})^{1/3}=2(\frac{3(10.8ft^3)}{4 \pi})^{1/3}= 2.74 ft$$
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