Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 1 - Introduction, Measurement, Estimating - General Problems - Page 19: 42

Answer

$2.5\times 10^{-4}m$

Work Step by Step

Assuming that the total volume of a typical human lung is 2.4 liters $(0.0024m^3)$ and that the alveoli are perfect spheres, we can find the diameter of an alveolus from the volume of a sphere, $\frac{4}{3}\pi r^{3}$ $$\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi (\frac{d}{2})^{3}=\frac{\pi d}{6}=1 alveolus$$ $$(3\times 10^{8})\frac{\pi d}{6}=0.0024m^3$$ $$d=\sqrt[3] (\frac{6(0.0024m^3)}{3\times 10^{8} \pi})$$ $$d=2.5\times 10^{-4}m$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.