Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 9 - Work and Kinetic Energy - Conceptual Questions: 1

Answer

The particle's kinetic energy increases by a factor of 9

Work Step by Step

We can write an expression for the particle's initial kinetic energy when the particle's speed is $v$. $KE_0 = \frac{1}{2}mv^2$ We can find the particle's kinetic energy when the speed is $3v$. $KE = \frac{1}{2}m(3v)^2$ $KE = 9\times ~\frac{1}{2}mv^2$ $KE = 9\times ~KE_0$ The particle's kinetic energy increases by a factor of 9.
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