Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 8 - Dynamics II: Motion in a Plane - Exercises and Problems: 5

Answer

The magnitude of the net force is 9400 N and this force points toward the center of the circle. The force of static friction between the ground and the tires provides this force.

Work Step by Step

The centripetal force is the net force which keeps an object moving in a circle. Therefore; $F_c = \frac{mv^2}{r}$ $F_c = \frac{(1500~kg)(25~m/s)^2}{100~m}$ $F_c = 9400~N$ The magnitude of the net force is 9400 N and this force points toward the center of the circle. The force of static friction between the ground and the tires provides this force.
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