Answer
The magnitude of the net force is 9400 N and this force points toward the center of the circle. The force of static friction between the ground and the tires provides this force.
Work Step by Step
The centripetal force is the net force which keeps an object moving in a circle. Therefore;
$F_c = \frac{mv^2}{r}$
$F_c = \frac{(1500~kg)(25~m/s)^2}{100~m}$
$F_c = 9400~N$
The magnitude of the net force is 9400 N and this force points toward the center of the circle. The force of static friction between the ground and the tires provides this force.
