## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 7 - Newton's Third Law - Exercises and Problems - Page 178: 21

#### Answer

The tension in the cable is 9800 N

#### Work Step by Step

Let $T_c$ be the tension in the cable car's cable. Let $T_b$ be the tension in the cable attached to the 2000-kg block. Then $T_b$ is equal to the weight of the 2000-kg block. From the diagram, we can see that the horizontal forces exerted on the cart are in equilibrium. We can use this fact to find the tension in the cable car's cable. $2~T_c = T_b$ $2~T_c = (2000~kg)(9.80~m/s^2)$ $T_c = \frac{(2000~kg)(9.80~m/s^2)}{2}$ $T_c = 9800~N$ The tension in the cable car's cable is 9800 N.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.