Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 7 - Newton's Third Law - Exercises and Problems - Page 177: 17


The tension in the rope is 590 N

Work Step by Step

The weight of the 60-kg person pulls down on the left side. However, the weight of the 100-kg block is on the right side. Therefore, the system will not start moving and the acceleration of the system is zero. We can consider the system of the person to find the tension in the rope. Let $m_p$ be the mass of the person; $\sum F = m_p~a$ $mg-T = (60~kg)(0)$ $T = mg$ $T = (60~kg)(9.80~m/s^2)$ $T = 590~N$ The tension in the rope is 590 N.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.