Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems - Page 157: 67

Answer

$14.14ms^{-1}$

Work Step by Step

The ball must come back with same speed as it was thrown with. lets compute the speed of ball with which it comes back to Nicole. we have $ u= 10ms^{-1}$, $a=g =10ms^{-2} $ and $ s= 5.0m$ $\therefore 2as =v^2 -u^2$ $ 2*10*5 = V^2 - 10^2$ $ v^2 = 200$ $ v= 14.14ms^{-1}$ hence speed of ball with which Nicole has thrown it up is $14.14 ms^{-1}$
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