## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

The force of kinetic friction will bring the suitcase up to a speed of 2.0 m/s. We can find the magnitude of acceleration. $F_f = ma$ $mg~\mu_k = ma$ $a = g~\mu_k$ $a = (9.80~m/s^2)(0.30)$ $a = 2.94~m/s^2$ We can find the distance the suitcase moves while the force of friction brings the suitcase up to a speed of 2.0 m/s. $x = \frac{v_f^2-v_0^2}{2a}$ $x = \frac{(2.0~m/s)^2-0}{(2)(2.94~m/s^2)}$ $x = 0.68~m$ The suitcase is dragged a distance of 0.68 meters before it is moving smoothly on the belt.