Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems - Page 154: 8

Answer

$a_x = -1.0~m/s^2$ $a_y = 0$

Work Step by Step

$F_x = -4.0~N + 2.0~N = -2.0~N$ $F_x = ma_x$ $a_x = \frac{F_x}{m}$ $a_x = \frac{-2.0~N}{2.0~kg}$ $a_x = -1.0~m/s^2$ $F_y = 3.0~N - 3.0~N = 0$ $F_y = ma_y$ $a_y = \frac{F_y}{m}$ $a_y = \frac{0}{2.0~kg}$ $a_y = 0$
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