## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) $a = 5~m/s^2$ (b) $a = 20~m/s^2$ (c) $a = 10~m/s^2$ (d) $a = 2.5~m/s^2$
$F = ma$ which can be written as: $a = \frac{F}{m} = 10~m/s^2$ So, (a) $a = \frac{(F/2)}{m} = \frac{10~m/s^2}{2} = 5~m/s^2$ (b) $a = \frac{F}{(m/2)} = (2)(10~m/s^2) = 20~m/s^2$ (c) $a = \frac{(F/2)}{(m/2)} = \frac{F}{m} = 10~m/s^2$ (d) $a = \frac{(F/2)}{(2m)} = \frac{F}{4m} = \frac{10~m/s^2}{4} = 2.5~m/s^2$