Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 5 - Force and Motion - Exercises and Problems - Page 128: 14


$F = 3.6~N$

Work Step by Step

From the graph we can see that the acceleration is $a = 18~m/s^2$ when the mass is $0.200~kg$. We can use this information to find $F$: $F = ma$ $F = (0.200~kg)(18~m/s^2)$ $F = 3.6~N$
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