## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) $a = 20~m/s^2$ (b) $a = 5~m/s^2$ (c) $a = 10~m/s^2$
$F = ma$ can be rearranged as; $a = \frac{F}{m} = 10~m/s^2$ Then; (a) $a = \frac{2F}{m} = (2)(10~m/s^2) = 20~m/s^2$ (b) $a = \frac{F}{2m} = \frac{10~m/s^2}{2} = 5~m/s^2$ (c) $a = \frac{2F}{2m} = \frac{F}{m} = 10~m/s^2$