Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 42 - Nuclear Physics - Exercises and Problems - Page 1237: 34


$E = 0.225~J$

Work Step by Step

We can find the energy that the tumor absorbs: $dose = \frac{E}{m}$ $E = (dose)\times (mass)$ $E = (1.5~Gy)\times (0.15~kg)$ $E = 0.225~J$
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