Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 4 - Kinematics in Two Dimensions - Exercises and Problems: 66

Answer

(a) The tangential acceleration is $0.966~m/s^2$ (b) The astronaut experiences 14 g's of acceleration.

Work Step by Step

(a) We can find the final angular speed. $\omega = \frac{2\pi~rad}{1.3~s}$ $\omega = 4.83~rad/s$ We can find the angular acceleration. $\alpha = \frac{\omega_f-\omega_0}{30~s}$ $\alpha = \frac{4.83~rad/s-0}{30~s}$ $\alpha = 0.161~rad/s^2$ We can find the tangential acceleration. $a = \alpha ~r$ $a = (0.161~rad/s^2)(6.0~m)$ $a = 0.966~m/s^2$ The tangential acceleration is $0.966~m/s^2$ (b) We can find the centripetal acceleration at top speed. $a_c = \omega^2~r$ $a_c = (4.83~rad/s)^2(6.0~m)$ $a_c = 140~m/s^2$ We can express this acceleration in g's. $a_c = \frac{140~m/s^2}{9.8~m/s^2} = 14~g's$ The astronaut experiences 14 g's of acceleration.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.