Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 4 - Kinematics in Two Dimensions - Exercises and Problems: 41

Answer

$\alpha = 47~rad/s^2$

Work Step by Step

We can convert 1800 rpm to units of rad/s: $\omega = (1800~rpm)(\frac{1~min}{60~s})(\frac{2\pi~rad}{1~rev})$ $\omega = 60\pi~rad/s$ We can find the angular acceleration; $\alpha = \frac{\omega}{t}$ $\alpha = \frac{60\pi~rad/s}{4.0~s}$ $\alpha = 47~rad/s^2$
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