## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

We can find the flight time of the ball; $y = \frac{1}{2}gt^2$ $t = \sqrt{\frac{2y}{g}}$ $t = \sqrt{\frac{(2)(4.0~m)}{9.80~m/s^2}}$ $t = 0.904~s$ We can find the ball's initial speed; $v_x = \frac{x}{t} = \frac{25~m}{0.904~s}$ $v_x = 27.7~m/s$ His pitching speed is 27.7 m/s