Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 38 - Quantization - Exercises and Problems - Page 1115: 38


$N = 3.32\times 10^{14}~photons$

Work Step by Step

We can find the energy of each photon: $E = \frac{h~c}{\lambda}$ $E = \frac{(6.626\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{550\times 10^{-9}~m}$ $E = 3.614\times 10^{-19}~J$ We can find the number of photons emitted in each flash: $N = \frac{P~\Delta t}{E}$ $N = \frac{(0.0012~W)(0.100~s)}{3.614\times 10^{-19}~J}$ $N = 3.32\times 10^{14}~photons$
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