Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 37 - The Foundation of Modern Physics - Exercises and Problems - Page 1081: 8

Answer

$6.25\times 10^{10}~~$ electrons strike the face of the glass tube each second.

Work Step by Step

We can write an expression for the current: $I = 10~nA = 1.0\times 10^{-8}~C/s$ Let $n$ be the number of electrons that strike the face of the glass tube each second: $n~q = 1.0\times 10^{-8}~C$ $n = \frac{1.0\times 10^{-8}~C}{q}$ $n = \frac{1.0\times 10^{-8}~C}{1.6\times 10^{-19}~C}$ $n = 6.25\times 10^{10}$ $6.25\times 10^{10}~~$ electrons strike the face of the glass tube each second.
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