Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 34 - Ray Optics - Exercises and Problems - Page 991: 25

Answer

$f = 30~cm$

Work Step by Step

We can find the focal length: $\frac{1}{f} = (n-1)(\frac{1}{R_1}-\frac{1}{R_2})$ $\frac{1}{f} = (1.50-1)(\frac{1}{24~cm}-\frac{1}{-40~cm})$ $\frac{1}{f} = (0.50)(\frac{5}{120~cm}+\frac{3}{120~cm})$ $\frac{1}{f} = (0.50)(\frac{1}{15~cm})$ $\frac{1}{f} = \frac{1}{30~cm}$ $f = 30~cm$
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