Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 31 - Electromagnetic Fields and Waves - Stop to Think 31.2 - Page 886: 1

Answer

$\vec{B}_c > \vec{B}_a > \vec{B}_d > \vec{B}_b$

Work Step by Step

Ampere's Law is as follows: $\displaystyle \oint\vec{B}\cdot d\vec{s} = \mu_0(I_{enclosed} + \epsilon_0\frac{d\Phi_E}{dt})$ Since we're given a graph of $\vec{E}$ vs. time, we need to find an equation that relates $\vec{B}$ to $\vec{E}$ $\displaystyle \oint\vec{B}\cdot d\vec{s} = \mu_0(I_{enclosed} + \epsilon_0\frac{d\Phi_E}{dt})$ $\displaystyle \vec{B} = \frac{\mu_0}{\vec{s}}(0 + \epsilon_0\frac{d}{dt}[\oint\vec{E}\cdot d\vec{A}])$ $\displaystyle \vec{B} = \frac{\mu_0\epsilon_0}{2\pi r}(\frac{d\vec{E}}{dt}\vec{A})$ $\displaystyle \vec{B} = \frac{\mu_0\epsilon_0A}{2\pi r} \frac{d\vec{E}}{dt}$ We see that $\vec{B}$ is directly related to $\displaystyle \frac{d\vec{E}}{dt}$. Because the question asks to rank the $strengths$ (which is the same thing as the magnitude) of the magnetic field, then the greater the slope of the line the stronger the magnetic field. Thus, the rankings are: $\vec{B}_c > \vec{B}_a > \vec{B}_d > \vec{B}_b$
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