Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 31 - Electromagnetic Fields and Waves - Exercises and Problems - Page 903: 54

Answer

$I = 4.9\times 10^7~W/m^2$

Work Step by Step

The required force is $F = mg$ We can find the required power $P$: $F = \frac{P}{c}$ $P = F~c$ $P = m~g~c$ $P = (1.0\times 10^{-3}~kg)(9.8~m/s^2)(3.0\times 10^8~m/s)$ $P = 2.94\times 10^6~W$ We can find the required intensity: $I = \frac{P}{A}$ $I = \frac{2.94\times 10^6~W}{(8.5~in)(0.0254~m/in)(11~in)(0.0254~m/in)}$ $I = 4.9\times 10^7~W/m^2$
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