Answer
$\theta = 60^{\circ}$
Work Step by Step
We can use Malus' Law:
$I = I_0~cos^2~\theta$
$0.25~I_0 = I_0~cos^2~\theta$
$cos^2~\theta = 0.25$
$cos~\theta = \sqrt{0.25}$
$cos~\theta = 0.50$
$\theta = cos^{-1}~(0.50)$
$\theta = 60^{\circ}$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 31 - Electromagnetic Fields and Waves - Exercises and Problems - Page 902: 24
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