#### Answer

The magnitude of C is 3.15 m and the magnitude of D is 25.6 m.
$C_x = -3.04~m$
$C_y = 0.815~m$
$D_x = 12.8~m$
$D_y = -22.2~m$

#### Work Step by Step

The magnitude of C is 3.15 m and the magnitude of D is 25.6 m. Therefore;
$C_x = -C~cos(\theta)$
$C_x = -(3.15~m)~cos(15^{\circ})$
$C_x = -3.04~m$
$C_y = C~sin(\theta)$
$C_y = (3.15~m)~sin(15^{\circ})$
$C_y = 0.815~m$
$D_x = D~sin(\theta)$
$D_x = (25.6~m)~sin(30^{\circ})$
$D_x = 12.8~m$
$D_y = -D~cos(\theta)$
$D_y = -(25.6~m)~cos(30^{\circ})$
$D_y = -22.2~m$