#### Answer

$B = 1.6\times 10^{-3}~T$

#### Work Step by Step

We can find the magnetic field:
$f = \frac{qB}{2\pi~m}$
$B = \frac{2\pi~m~f}{q}$
$B = \frac{(2\pi)~(9.1\times 10^{-31}~kg)~(45\times 10^6~Hz)}{1.6\times 10^{-19}~C}$
$B = 1.6\times 10^{-3}~T$

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Published by
Pearson

ISBN 10:
0133942651

ISBN 13:
978-0-13394-265-1

$B = 1.6\times 10^{-3}~T$

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