Answer
$B = 1.6\times 10^{-3}~T$
Work Step by Step
We can find the magnetic field:
$f = \frac{qB}{2\pi~m}$
$B = \frac{2\pi~m~f}{q}$
$B = \frac{(2\pi)~(9.1\times 10^{-31}~kg)~(45\times 10^6~Hz)}{1.6\times 10^{-19}~C}$
$B = 1.6\times 10^{-3}~T$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 29 - The Magnetic Field - Exercises and Problems - Page 831: 28
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