Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 28 - Fundamentals of Circuits - Conceptual Questions - Page 789: 1

Answer

We can rank the currents in order from largest to smallest: $I_c \gt I_a = I_d \gt I_b$

Work Step by Step

We can find the current in each case: (a) $I_a = \frac{V}{R} = \frac{2~V}{2~\Omega} = 1~A$ (b) $I_b = \frac{V}{R} = \frac{1~V}{2~\Omega} = \frac{1}{2}~A$ (c) $I_c = \frac{V}{R} = \frac{2~V}{1~\Omega} = 2~A$ (d) $I_d = \frac{V}{R} = \frac{1~V}{1~\Omega} = 1~A$ We can rank the currents in order from largest to smallest: $I_c \gt I_a = I_d \gt I_b$
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