Answer
The blood resistivity is 1.39Ωm
Work Step by Step
Find the resistance of the given portion of blood,
$V=IR$
$9.0 V= 230\mu A \times R$
$R= 39.1$ $kΩ$
$R=\frac{\rho l}{A}$
$\rho=\frac{RA}{l}$
Area of the vein = $π(\frac{d}{2})^{2} = π(1.5 mm)/2)^{2} = 1.75 \times 10^{-6} m^{2}$
Substitute values in above equation to find resistivity
$\rho=\frac{(39.1 \times 10^{3})(1.75 \times 10^{-6} m^{2})}{5 \times 10^{-2}m} = 1.3935 Ωm \approx 1.39Ωm$
