Answer
The current is $~2.0\times 10^{-5}~C/s$
Work Step by Step
We can find the current:
$Q = C~V$
$\frac{dQ}{dt} = C~(\frac{dV}{dt})$
$\frac{dQ}{dt} = (10\times 10^{-6}~F)~(2.0~V/s)$
$\frac{dQ}{dt} = 2.0\times 10^{-5}~C/s$
The current is $~2.0\times 10^{-5}~C/s$
