Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 25 - The Electric Potential - Conceptual Questions - Page 708: 10


(a) $\frac{V_{2}}{V_{1}}=\frac{1}{3}$ (b) $\frac{E_{2}}{E_{1}}=\frac{1}{9}$

Work Step by Step

(a) $\frac{V_{2}}{V_{1}}=\frac{r_{1}}{r_{2}}$ (since, charge $q$ is same and $V=\frac{q}{4 \pi \epsilon_{0}r}$) Therefore, $\frac{V_{2}}{V_{1}}=\frac{1}{3}$. (b) $\frac{E_{2}}{E_{1}}=\frac{r_{1}^{2}}{r_{2}^{2}}$ (since, charge $q$ is same and $E=\frac{q}{4 \pi \epsilon_{0}r^{2}}$) Therefore, $\frac{E_{2}}{E_{1}}=\frac{1}{3^{2}}=\frac{1}{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.