Answer
$106.02\times 10^{-2}Nm^{2}/C$
Work Step by Step
Given:
$d=3cm$, so $r=1.5\times 10^{-2}m^{2}$
$A=\pi (1.5\times 10^{-2}m)^{2}j=2.25\pi\times 10^{-4}m^{2}j$ (plane xz)
$E=1500i+1500j-1500k$
Electric flux $\phi$ through any surface is given as
$ \phi= E.A$
Thus,$\phi=(1500i+1500j-1500k)\times(2.25\pi\times 10^{-4}j)$
Hence,
$\phi=1500\times2.25\pi\times 10^{-4}=106.02\times 10^{-2}Nm^{2}/C$
