#### Answer

$\phi_{a}=\frac{q}{\epsilon_0}$
$\phi_{b}=-\frac{q}{\epsilon_0}$
$\phi_{c}=0$

#### Work Step by Step

Flux through a body due to charges present outside is 0. So, there will be flux only due to charges present inside the body.
1.Charge in figure (a) $=q$ so, electric flux through $\phi_{a}=\frac{q}{\epsilon_0}$
2. Charge in figure (b) $=-q$ so, electric flux through $\phi_{b}=-\frac{q}{\epsilon_0}$
3. Charge in figure (c) $=0$ so, electric flux through $\phi_{c}=0$
Hence,
$\phi_{a}=\frac{q}{\epsilon_0}$
$\phi_{b}=-\frac{q}{\epsilon_0}$
$\phi_{c}=0$