#### Answer

The $x-$intercept is $(6,\,0)$.
The $y-$intercept is $(0,\,-4)$.
The graph of the line is as shown below:

#### Work Step by Step

To find the $x-$intercept, substitute $y=0$ in the equation$2x-3y=12$.
$\Rightarrow 2x-3\left( 0 \right)=12$,
$\Rightarrow 2x=12$.
Divide on both sides by $12$,
$\Rightarrow x=6$.
The $x-$intercept is $6$, and the point $\left( 6,0 \right)$ is on the graph of the equation.
To find the $x-$intercept, substitute $x=0$ in the equation $2x-3y=12$.
$\Rightarrow 2\left( 0 \right)-3y=12$,
$\Rightarrow -3y=12$.
Divide on both sides by $-3$,
$\Rightarrow y=-4$.
The $y-$intercept is $-4$, and the point $\left( 0,-4 \right)$ is on the graph of the equation.
To draw the graph of the equation of the line $2x-3y=12$, plot the points $\left( 0,-4 \right)$ and $\left( 6,0 \right)$, and connect them to each other.