Answer
$v = 7.3~m/s$
Work Step by Step
We can find the net force on the spaceship due to electric charges and the gravitational force:
$F = \vert \frac{kq_1~q_2}{r^2} \vert+\frac{G~m_1~m_2}{r^2}$
$F = \frac{(9.0\times 10^9~N~m^2/C^2)(4400~C)(1.2~C)}{(3.75\times 10^6~m)^2} + \frac{(6.67\times 10^{-11}~N~m^2/kg^2)(3.3\times 10^5~kg)(8.7\times 10^{17}~kg)}{(3.75\times 10^6~m)^2}$
$F = 4.74~N$
We can find the required speed:
$F = \frac{mv^2}{r}$
$v^2 = \frac{F~r}{m}$
$v = \sqrt{\frac{F~r}{m}}$
$v = \sqrt{\frac{(4.74~N)(3.75\times 10^6~m)}{3.3\times 10^5~kg}}$
$v = 7.3~m/s$
