#### Answer

(a) Tina drives 900 meters.
(b) v = 60 m/s

#### Work Step by Step

(a) We can equate the distance traveled by David and Tina to find the time it takes Tina to pass David;
$\frac{1}{2}at^2=v~t$
$t = \frac{2v}{a} = \frac{(2)(30~m/s)}{2.0~m/s^2}$
$t = 30~s$
We can find the distance that Tina travels in 30 seconds.
$x = \frac{1}{2}at^2$
$x = \frac{1}{2}(2.0~m/s^2)(30~s)^2$
$x = 900~m$
Tina drives 900 meters.
(b) $v = a~t = (2.0~m/s^2)(30~s)$
$v = 60~m/s$