#### Answer

Bob is in jail.

#### Work Step by Step

We can find the distance the car moves in 0.60 seconds;
$d = v~t = (50~m/s)(0.60~s)$
$d = 30~m$
We can find the distance $x$ the car travels during the braking period;
$x = \frac{v^2-v_0^2}{2a}$
$x = \frac{0-(50~m/s)^2}{(2)(-10~m/s^2)}$
$x = 125~m$
The car travels a total distance of 125 m + 30 m which is 155 meters. Since the car needed to stop within 150 meters, Bob is in jail.