Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 18 - A Macroscopic Description of Matter - Exercises and Problems - Page 511: 25

Answer

The number density of particles in the solar corona is $1.09\times 10^{15}~particles/m^3$

Work Step by Step

We use the formula below to find the number of particles: $PV = NkT$ $\frac{N}{V} = \frac{P}{kT}$ $\frac{N}{V} = \frac{0.03~Pa}{(1.38\times 10^{-23}~J/K)(2\times 10^6~K)}$ $\frac{N}{V} = 1.09\times 10^{15}~particles/m^3$ The number density of particles in the solar corona is thus $1.09\times 10^{15}~particles/m^3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.