Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 16 - Traveling Waves - Exercises and Problems: 60

Answer

$v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$

Work Step by Step

The tension in the string is equal to the component of the block's weight directed down the slope. We can find the tension in the string. $T = Mg~sin(\theta)$ We can find an expression for the speed of the waves on the string. $v = \sqrt{\frac{T}{\mu}}$ $v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$
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