## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$
The tension in the string is equal to the component of the block's weight directed down the slope. We can find the tension in the string. $T = Mg~sin(\theta)$ We can find an expression for the speed of the waves on the string. $v = \sqrt{\frac{T}{\mu}}$ $v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$