# Chapter 16 - Traveling Waves - Exercises and Problems - Page 452: 37

$E = 3.4\times 10^{-6}~J$

#### Work Step by Step

We can find the power received by the eardrum. $P = I~A$ $P = I~(\pi~R^2)$ $P = (2.0\times 10^{-3}~W/m^2)(\pi)(0.0030~m)^2$ $P = 5.65\times 10^{-8}~W$ We can find the energy transferred to the eardrum while listening for 1.0 minute. $E = P~t$ $E = (5.65\times 10^{-8}~W)(60~s)$ $E = 3.4\times 10^{-6}~J$

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