## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) $\lambda = 4.2~m$ (b) $f = 48~Hz$
(a) We can find the wavelength as: $k = \frac{2\pi}{\lambda}$ $\lambda = \frac{2\pi}{k}$ $\lambda = \frac{2\pi}{1.5~rad/m}$ $\lambda = 4.2~m$ (b) We can find the frequency as: $f = \frac{v}{\lambda}$ $f = \frac{200~m/s}{4.2~m}$ $f = 48~Hz$