## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$\lambda_1 \gt \lambda_2 \gt \lambda_3$
Let $v$ be the speed of sound. Given the frequency $f$, we can write an expression for the wavelength; $\lambda = \frac{v}{f}$ From this equation, we can see that the wavelength decreases as the frequency increases. We know that $f_3 \gt f_2 \gt f_1$. Therefore: $\lambda_1 \gt \lambda_2 \gt \lambda_3$