## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

$V = 50~mL$
We can find the volume in units of $m^3$.; $V = \frac{M}{\rho}$ $V = \frac{0.055~kg}{1100~kg/m^3}$ $V = 5.0\times 10^{-5}~m^3$ We can convert the volume to units of mL; $V = (5.0\times 10^{-5}~m^3)(\frac{10^6~mL}{1~m^3})$ $V = 50~mL$