# Line slope calculator 3x+2y=19

**Straight line given by points A[1; 8] and B[3; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.5x+9.5

**Canonical form of the line equation:**3x+2y-19 = 0

**Parametric form of the line equation:**

x = 2t+1

y = -3t+8 ; t ∈ R

**Slope:**m = -1.5

**Slope angle of line: φ =**-56°18'36″ = -0.9828 rad

**X intercept:**x

_{0}= 6.3333

**Y intercept:**y

_{0}= q = 9.5

**Distance line from the origin:**d

_{0}= 5.2697

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(2; -3)

**Normal vector: n =**(3; 2)

**Midpoint of the segment AB: M =**[2; 6.5]

**Perpendicular Bisector equation:**2x-3y+15.5 = 0

**Vector OA = (1; 8) ; |OA| = 8.0623**

**Vector OB = (3; 5) ; |OB| = 5.831**

**Scalar product OA .OB = 43**

**Angle ∠ AOB = 23°50'19″ = 0.4161 rad**