## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 14 - Fluids and Elasticity - Conceptual Questions - Page 383: 12

#### Answer

A force of 4000 N is needed to stretch the wire by 1 mm.

#### Work Step by Step

We can use Young's modulus to solve this question: $Y = \frac{F/A}{\Delta~L/L}$ We can find an expression for the force required to stretch a wire; $Y = \frac{F/A}{\Delta~L/L}$ $F = \frac{Y~A~\Delta L}{L}$ $F = \frac{Y~\pi~R^2~\Delta L}{L}$ We can write an expression for $F_1$; $F_1 = \frac{Y~\pi~R_1^2~\Delta L}{L_1}$ We can write an expression for $F_2$; $F_2 = \frac{Y~\pi~(2R_1)^2~\Delta L}{2L_1}$ $F_2 = 2\times\frac{Y~\pi~R_1^2~\Delta L}{L_1}$ $F_2 = 2~F_1$ $F_2 = (2)(2000~N)$ $F_2 = 4000~N$ A force of 4000 N is needed to stretch the wire by 1 mm.

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