Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 11 - Impulse and Momentum - Exercises and Problems: 30

Answer

The lighter ball has a speed of $3~v_0$

Work Step by Step

Since the initial momentum of the system of two balls is zero, the magnitude of the lighter ball's final momentum $p_L$ should be equal to the magnitude of the heavier ball's final momentum $p_H$. We can equate the magnitudes of the momenta to find the speed $v$ of the lighter ball. $p_L = p_H$ $m~v = 3m~v_0$ $v = 3~v_0$ The lighter ball has a speed of $3~v_0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.