Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 11 - Impulse and Momentum - Exercises and Problems - Page 287: 19

Answer

$0.9 \frac{m}{s}$

Work Step by Step

We apply the conservation of momentum by letting $p_v$ and $p_c$ be the momentum of the Volkswagen and Cadillac, respectively. $p_v=p_c$ We expand to the definition of momentum: $m_vv_v=m_cv_c$ Since we are given $m_c = 2000 kg$ $v_c = 0.45 \frac m s$ ( by conversion from mph to ms) $m_v = 1000 kg$ We need to solve for $v_v$, the velocity of the Volkswagen: $\frac{m_cv_c}{m_v}=v_v$ Substituting all the known values in, we get the final answer $\frac{(2000 kg)(0.45 \frac m s)}{1000 kg} = \boxed{0.9 \frac m s}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.