Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 10 - Interactions and Potential Energy - Exercises and Problems - Page 258: 42


The ice cube goes up to a height of 0.26 m

Work Step by Step

The block's potential energy at the maximum height will be equal to the initial energy stored in the spring. We can find the maximum height $h$ as: $PE = U_s$ $mgh = \frac{1}{2}k(\Delta x)^2$ $h = \frac{k~(\Delta x)^2}{2mg}$ $h = \frac{(25~N/m)(0.10~m)^2}{(2)(0.050~kg)(9.80~m/s^2)}$ $h = 0.26~m$ The ice cube goes up to a height of 0.26 m.
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