Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 10 - Interactions and Potential Energy - Exercises and Problems: 42

Answer

The ice cube goes up to a height of 0.26 m

Work Step by Step

The block's potential energy at the maximum height will be equal to the initial energy stored in the spring. We can find the maximum height $h$ as: $PE = U_s$ $mgh = \frac{1}{2}k(\Delta x)^2$ $h = \frac{k~(\Delta x)^2}{2mg}$ $h = \frac{(25~N/m)(0.10~m)^2}{(2)(0.050~kg)(9.80~m/s^2)}$ $h = 0.26~m$ The ice cube goes up to a height of 0.26 m.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.