## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

(a) At the midpoint between point A and point B, the potential energy is at a maximum of 5.0 J. For the particle at point A to reach point B, the total energy must be at least 5.0 J. We can find the minimum kinetic energy required at point A. $K+U = E$ $K = E-U$ $K = 5.0~J - 2.0~J$ $K = 3.0~J$ We can find the minimum speed of the particle at point A. $K = 3.0~J$ $\frac{1}{2}mv^2 = 3.0~J$ $v^2 = \frac{(2)(3.0~J)}{m}$ $v = \sqrt{\frac{(2)(3.0~J)}{m}}$ $v = \sqrt{\frac{(2)(3.0~J)}{0.10~kg}}$ $v = 7.7~m/s$ At point A, the minimum speed required to reach point B is 7.7 m/s (b) At the midpoint between point A and point B, the potential energy is at a maximum of 5.0 J. For the particle at point B to reach point A, the total energy must be at least 5.0 J. We can find the minimum kinetic energy required at point B. $K+U = E$ $K = E-U$ $K = 5.0~J - 0$ $K = 5.0~J$ We can find the minimum speed of the particle at point B. $K = 5.0~J$ $\frac{1}{2}mv^2 = 5.0~J$ $v^2 = \frac{(2)(5.0~J)}{m}$ $v = \sqrt{\frac{(2)(5.0~J)}{m}}$ $v = \sqrt{\frac{(2)(5.0~J)}{0.10~kg}}$ $v = 10~m/s$ At point B, the minimum speed required to reach point A is 10 m/s